動機
處理backtrack的重複就是在同一層展開完,再到下一層去
Problem
Given a collection of candidate numbers (candidates
) and a target number (target
), find all unique combinations in candidates
where the candidate numbers sum to target
.
Each number in candidates
may only be used once in the combination.
Note: The solution set must not contain duplicate combinations.
Example 1:
Input: candidates = [10,1,2,7,6,1,5], target = 8Output: [[1,1,6],[1,2,5],[1,7],[2,6]]
Example 2:
Input: candidates = [2,5,2,1,2], target = 5Output: [[1,2,2],[5]]
Constraints:
1 <= candidates.length <= 100
1 <= candidates[i] <= 50
1 <= target <= 30
Sol
class Solution:
def combinationSum2(self, cs: List[int], val: int) -> List[List[int]]:
def bt(cs,acc,cnt):
if val == cnt:
return [acc]
elif cnt > val or not cs:
return []
else:
now = cs[0]
j = bisect_right(cs,now)
return sum([bt(cs[j:],acc+([now]*i),cnt+now*i) for i in range(j+1)],[])
cs.sort()
return bt(cs,[],0)