動機
Monotonic Stack在pop時當下的狀態是
7 3 2 .left. 1 .right. 2
right的數字大小一定是大於1!! left的數字一定是等於1
代表說在這個區間1一定是最小的 但哪邊是最大? 就要比較左右兩邊了
Problem
Given an array arr
of positive integers, consider all binary trees such that:
- Each node has either
0
or2
children; - The values of
arr
correspond to the values of each leaf in an in-order traversal of the tree. - The value of each non-leaf node is equal to the product of the largest leaf value in its left and right subtree, respectively.
Among all possible binary trees considered, return the smallest possible sum of the values of each non-leaf node. It is guaranteed this sum fits into a 32-bit integer.
A node is a leaf if and only if it has zero children.
Example 1:
Input: arr = [6,2,4]Output: 32Explanation: There are two possible trees shown.The first has a non-leaf node sum 36, and the second has non-leaf node sum 32.
Example 2:
Input: arr = [4,11]Output: 44
Constraints:
2 <= arr.length <= 40
1 <= arr[i] <= 15
- It is guaranteed that the answer fits into a 32-bit signed integer (i.e., it is less than 231).
Sol
class Solution:
def mctFromLeafValues(self, arr: List[int]) -> int:
stk, ret = [], 0
for n in arr:
while stk and stk[-1] <= n:
minN = stk.pop()
if stk:
ret += min(stk[-1], n)*minN
else:
ret += minN*n
stk += n,
return ret+sum([a*b for a,b in zip(stk[:-1], stk[1:])],0)