動機
有趣的數學題
Problem
There are n
bulbs that are initially off. You first turn on all the bulbs, then you turn off every second bulb.
On the third round, you toggle every third bulb (turning on if it's off or turning off if it's on). For the ith
round, you toggle every i
bulb. For the nth
round, you only toggle the last bulb.
Return the number of bulbs that are on after n
rounds.
Example 1:
Input: n = 3Output: 1Explanation: At first, the three bulbs are [off, off, off].After the first round, the three bulbs are [on, on, on].After the second round, the three bulbs are [on, off, on].After the third round, the three bulbs are [on, off, off]. So you should return 1 because there is only one bulb is on.
Example 2:
Input: n = 0Output: 0
Example 3:
Input: n = 1Output: 1
Constraints:
0 <= n <= 109
Sol
任何平方數都是1,n,n^2
,所以平方數到最後一定會亮!!
class Solution:
def bulbSwitch(self, n: int) -> int:
return math.floor(math.sqrt(n))